A suitable 'do nothing' lambda expression in python?
If you truly want a full do nothing lambda function, make sure to gobble up *args
and *kwargs
.
noop = lambda *args, **kwargs: None
In all its glorious action
>>> noop = lambda *args, **kwargs: None
>>> noop("yes", duck_size="horse", num_ducks=100)
>>>
Side Note
Since the accepted answer is only using *args
, I must point out that you will do yourself a favor for the future by including the **kwargs
handling. If you ever try to use the noop
somewhere deep away in your code and you forgot that it doesn't take kwargs
, it will be quite the Exception to doing nothing:
In [2]: do_nothing('asdf', duck="yes")
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-2-efbd722f297c> in <module>()
----> 1 do_nothing('asdf', duck="yes")
TypeError: <lambda>() got an unexpected keyword argument 'duck'
This:
def do_nothing(*args):
pass
is equivalent to:
lambda *args: None
With some minor differences in that one is a lambda
and one isn't. (For example, __name__
will be do_nothing
on the function, and <lambda>
on the lambda.) Don't forget about **kwargs
, if it matters to you. Functions in Python without an explicit return <x>
return None
. This is here:
A call always returns some value, possibly None, unless it raises an exception.
I've used similar functions as default values, say for example:
def long_running_code(progress_function=lambda percent_complete: None):
# Report progress via progress_function.