Accessing the ScrollViewer of a ListBox from C#
you can try this little helper function
usage
var scrollViewer = GetDescendantByType(yourListBox, typeof(ScrollViewer)) as ScrollViewer;
helper function
public static Visual GetDescendantByType(Visual element, Type type)
{
if (element == null) {
return null;
}
if (element.GetType() == type) {
return element;
}
Visual foundElement = null;
if (element is FrameworkElement) {
(element as FrameworkElement).ApplyTemplate();
}
for (int i = 0; i < VisualTreeHelper.GetChildrenCount(element); i++) {
Visual visual = VisualTreeHelper.GetChild(element, i) as Visual;
foundElement = GetDescendantByType(visual, type);
if (foundElement != null) {
break;
}
}
return foundElement;
}
Hope this helps
If you will use standard ListBox, so you can change yours getter to this one:
public class MyListBox : ListBox
{
public ScrollViewer ScrollViewer
{
get
{
Border border = (Border)VisualTreeHelper.GetChild(this, 0);
return (ScrollViewer)VisualTreeHelper.GetChild(border, 0);
}
}
}
I've modified the great answer of @punker76 to create an extension method for Visual and provide explicit return type:
public static class Extensions
{
public static T GetDescendantByType<T>(this Visual element) where T:class
{
if (element == null)
{
return default(T);
}
if (element.GetType() == typeof(T))
{
return element as T;
}
T foundElement = null;
if (element is FrameworkElement)
{
(element as FrameworkElement).ApplyTemplate();
}
for (var i = 0; i < VisualTreeHelper.GetChildrenCount(element); i++)
{
var visual = VisualTreeHelper.GetChild(element, i) as Visual;
foundElement = visual.GetDescendantByType<T>();
if (foundElement != null)
{
break;
}
}
return foundElement;
}
}
You can now call it by SomeVisual.GetDescendantByType and it returns either already a correct typed ScrollViewer or null (which is default(T))