android : Open pop-up window in my webview
Add this line to your web view web.addJavascriptInterface(new Jscalls(this), "Android");
Then add this line to your href in html that is loaded in the web view href="javascript:showAndroidToast('Data to be shown or the URL from which data is to be shown')"
public class Jscalls {
Context mContext;
Jscalls(Context c) {
mContext = c;
}
/** Show a toast from the web page */
@JavascriptInterface
public void showToast(final String toast) {
// Toast.makeText(mContext, toast, Toast.LENGTH_SHORT).show();
if (NetworkConnection.isConnected(mContext)) {
((Activity)mContext).runOnUiThread(new Runnable() {
public void run() {
dialog = new Dialog(mContext);
dialog.setTitle("Title");
dialog.setContentView(R.layout.dialog);
dialog.setCancelable(true);
// there are a lot of settings, for dialog, check them all out!
// set up text
WebView web = (WebView) dialog.findViewById(R.id.webVie);
web.getSettings().setJavaScriptEnabled(true);
/*web.clearHistory();
web.clearFormData();
web.clearCache(true);*/
web.setWebViewClient(new HelloWebViewClient());
web.setOnLongClickListener(new OnLongClickListener() {
@Override
public boolean onLongClick(View v) {
return true;
}
});
web.setLongClickable(false);
try{
web.loadUrl(Url.mainUrl
+ toast);//Url to load data from in pop-up
}catch (Exception e) {
// TODO: handle exception
//e.printStackTrace();
}
// dialog.setContentView(web);
dialog.show();
}
});
//web = null ;
// now that the dialog is set up, it's time to show it
/*
* dialog.setFeatureDrawableResource(Window.FEATURE_LEFT_ICON,
* R.drawable.ic_launcher);
*/
// dialog.setFeatureDrawable
} else {
LoginMainActivity.validateEmail("Alert!!",
"This feature requires wi-fi or internet connection.",
mContext);
}
}
private class HelloWebViewClient extends WebViewClient {
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);
return true;
}
}
Dialog dialog;
}
I am answering my own question after 3 long years:
When a link is touched inside a webpage then depending on a webpage implementation there are two possible scenarios: 1) Link will be opened in same window. 2) Link will be opened in new window.
Well Its easy to handle 1st scenario using below code:
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);
return true;
}
Overiding shouldOverrideUrlLoading inside WebViewClient implementation will open link in same window.
Now lets look at the 2nd case, where webpage is requesting a url to be open in new window. For this case we need to tell our webview to support multiple windows like below:
webView.getSettings().setSupportMultipleWindows(true);
and then adding a new web chrome client to webview to get event when new window is requested by webpage
webView.setWebChromeClient(new WebChromeClient() {
@Override
public boolean onCreateWindow(WebView view, boolean isDialog,
boolean isUserGesture, Message resultMsg) {
WebView newWebView = new WebView(WebpageActivity.this);
newWebView.getSettings().setJavaScriptEnabled(true);
newWebView.getSettings().setSupportZoom(true);
newWebView.getSettings().setBuiltInZoomControls(true);
newWebView.getSettings().setPluginState(PluginState.ON);
newWebView.getSettings().setSupportMultipleWindows(true);
view.addView(newWebView);
WebView.WebViewTransport transport = (WebView.WebViewTransport) resultMsg.obj;
transport.setWebView(newWebView);
resultMsg.sendToTarget();
newWebView.setWebViewClient(new WebViewClient() {
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);
return true;
}
});
return true;
}
}
});
Cheers!!!