Angular 2 - Debouncing a keyUp event

An Update for Rx/JS 6. Using the Pipe Operator.

import { debounceTime } from 'rxjs/operators';

this.subject.pipe(
      debounceTime(500)
    ).subscribe(searchTextValue => {
      this.handleSearch(searchTextValue);
    });

Everything else is the same 👍

UPDATE: Using RXJS 6 pipe operator:

this.subject.pipe(
  debounceTime(500)
).subscribe(searchTextValue => {
  this.handleSearch(searchTextValue);
});

---

You could create a rxjs/Subject and call .next() on keyup and subscribe to it with your desired debounceTime.

I'm not sure if it is the right way to do it but it works.

private subject: Subject<string> = new Subject();

ngOnInit() {
  this.subject.debounceTime(500).subscribe(searchTextValue => {
    this.handleSearch(searchTextValue);
  });
}

onKeyUp(searchTextValue: string){
  this.subject.next(searchTextValue);
}

HTML:

<input (keyup)="onKeyUp(searchText.value)">

Take a look at answer here: https://stackoverflow.com/a/35992325/751200

And article here: https://blog.thoughtram.io/angular/2016/01/06/taking-advantage-of-observables-in-angular2.html (quite old, but still good).

Basically, you can use an Observable object provided by Angular Forms.

For example, this.myFormGroup.get("searchText").valueChanges.pipe(debounceTime(500), distinctUntilChanged()).subscribe(...)

If you need to perform an HTTP request when user stops typing, you can place such HTTP call into switchMap operator and add it to pipe list:

this.myFormGroup.get("searchText")
                .valueChanges
                .pipe(debounceTime(500),
                      distinctUntilChanged(), 
                      switchMap((value: string) => {
                          return this.service.getData(value);
                      }))
                .subscribe((valueFromRest) => { ... });

The magic in switchMap will automatically cancel the previous HTTP request (if it's not completed yet) and start a new one automatically.