argparse: identify which subparser was used
Edit: Please see quornian's answer to this question, which is better than mine and should be the accepted answer.
According to the argparse documentation the result of parser.parse_args(...)
will "only contain attributes for the main parser and the sub parser that was selected". Unfortunately this may not be enough information to determine which sub parser was used. The documentation recommends using the set_defaults(...)
method on the sub parser to solve this problem.
For example, I've added calls to set_defaults()
to your code:
import argparse
parser = argparse.ArgumentParser( version='pyargparsetest 1.0' )
subparsers = parser.add_subparsers(help='commands')
# all
all_parser = subparsers.add_parser('all', help='process all apps')
all_parser.set_defaults(which='all')
# app
app_parser = subparsers.add_parser('app', help='process a single app')
app_parser.add_argument('appname', action='store', help='name of app to process')
app_parser.set_defaults(which='app')
Now if you run
print parser.parse_args(["all"])
The result is
Namespace(which='all')
Check out the add_subparsers()
documentation for more information and another example.
A simpler solution is to add dest
to the add_subparsers
call. This is buried a bit further down in the documentation:
[...] If it is necessary to check the name of the subparser that was invoked, the dest keyword argument to the add_subparsers() call will work
In your example replace:
subparsers = parser.add_subparsers(help='commands')
with:
subparsers = parser.add_subparsers(help='commands', dest='command')
Now if you run:
print parser.parse_args(["all"])
you will get
Namespace(command='all')