Bash Prompt with Last Exit Code
As you are starting to border on a complex PS1, you might consider using PROMPT_COMMAND
.
With this, you set it to a function, and it will be ran after each command to generate the prompt.
You could try the following in your ~/.bashrc
PROMPT_COMMAND=__prompt_command # Func to gen PS1 after CMDs
__prompt_command() {
local EXIT="$?" # This needs to be first
PS1=""
local RCol='\[\e[0m\]'
local Red='\[\e[0;31m\]'
local Gre='\[\e[0;32m\]'
local BYel='\[\e[1;33m\]'
local BBlu='\[\e[1;34m\]'
local Pur='\[\e[0;35m\]'
if [ $EXIT != 0 ]; then
PS1+="${Red}\u${RCol}" # Add red if exit code non 0
else
PS1+="${Gre}\u${RCol}"
fi
PS1+="${RCol}@${BBlu}\h ${Pur}\W${BYel}$ ${RCol}"
}
This should do what it sounds line you want.
Take a look a my bashrc's sub file if you want to see all the things I do with my __prompt_command
function.
If you don't want to use the prompt command there's two things you need to take into account:
- getting the value of $? before anything else, otherwise it'll be overriden
- escaping all the $'s in the PS1 (so it's not evaluated when you assign it)
Working example using a variable
PS1="\$(VALU="\$?" ; echo \$VALU ; date ; if [ \$VALU == 0 ]; then echo zero; else echo nonzero; fi) "
Working example without a variable
Here the if needs to be the first thing, before any command that would override the $?
.
PS1="\$(if [ \$? == 0 ]; then echo zero; else echo nonzero; fi) "
Notice how the \$()
is escaped so it's not executed right away but each time PS1 is used. Also all the uses of \$?
I wanted to keep default Debian colors, print the exact code, and only print it on failure:
# Show exit status on failure.
PROMPT_COMMAND=__prompt_command
__prompt_command() {
local curr_exit="$?"
local BRed='\[\e[0;91m\]'
local RCol='\[\e[0m\]'
PS1='${debian_chroot:+($debian_chroot)}\[\033[01;32m\]\u@\h\[\033[00m\]:\[\033[01;34m\]\w\[\033[00m\]\$ '
if [ "$curr_exit" != 0 ]; then
PS1="[${BRed}$curr_exit${RCol}]$PS1"
fi
}