Bash: Take the first command line argument and pass the rest

You can use shift

shift is a shell builtin that operates on the positional parameters. Each time you invoke shift, it "shifts" all the positional parameters down by one. $2 becomes $1, $3 becomes $2, $4 becomes $3, and so on

example:

$ function foo() { echo $@; shift; echo $@; } 
$ foo 1 2 3
1 2 3
2 3

As a programmer I would strongly recommend against shift because operations that modify the state can affect large parts of a script and make it harder to understand, modify, and debug:sweat_smile:. You can instead use the following:

#!/usr/bin/env bash

all_args=("$@")
first_arg=$1
second_args=$2
rest_args=("${all_args[@]:2}")

echo "${rest_args[@]}"