Best practice for Swift methods that can return or error
If you want to handle errors that can happen during login process than use the power of Swift error handling:
struct User {
}
enum SecurityError: Error {
case emptyEmail
case emptyPassword
}
class SecurityService {
static func loginWith(email: String, password: String) throws -> User {
if email.isEmpty {
throw SecurityError.emptyEmail
}
if password.isEmpty {
throw SecurityError.emptyPassword
}
return User()
}
}
do {
let user = try SecurityService.loginWith1(email: "", password: "")
} catch SecurityError.emptyEmail {
// email is empty
} catch SecurityError.emptyPassword {
// password is empty
} catch {
print("\(error)")
}
Or convert to optional:
guard let user = try? SecurityService.loginWith(email: "", password: "") else {
// error during login, handle and return
return
}
// successful login, do something with `user`
If you just want to get User
or nil
:
class SecurityService {
static func loginWith(email: String, password: String) -> User? {
if !email.isEmpty && !password.isEmpty {
return User()
} else {
return nil
}
}
}
if let user = SecurityService.loginWith(email: "", password: "") {
// do something with user
} else {
// error
}
// or
guard let user = SecurityService.loginWith(email: "", password: "") else {
// error
return
}
// do something with user
Besides the standard way to throw
errors you can use also an enum
with associated types as return type
struct User {}
enum LoginResult {
case success(User)
case failure(String)
}
class SecurityService {
static func loginWith(email: String, password: String) -> LoginResult {
if email.isEmpty { return .failure("Email is empty") }
if password.isEmpty { return .failure("Password is empty") }
return .success(User())
}
}
And call it:
let result = SecurityService.loginWith("Foo", password: "Bar")
switch result {
case .Success(let user) :
print(user)
// do something with the user
case .Failure(let errormessage) :
print(errormessage)
// handle the error
}