binary search string java example
Example 1: binary search java
class BinarySearch {
int binarySearch(int arr[], int x)
{
int l = 0, r = arr.length - 1;
while (l <= r) {
int m = l + (r - l) / 2;
if (arr[m] == x)
return m;
if (arr[m] < x)
l = m + 1;
else
r = m - 1;
}
return -1;
}
public static void main(String args[])
{
BinarySearch ob = new BinarySearch();
int arr[] = { 2, 3, 4, 10, 40 };
int n = arr.length;
int x = 10;
int result = ob.binarySearch(arr, x);
if (result == -1)
System.out.println("Element not present");
else
System.out.println("Element found at "
+ "index " + result);
}
}
Example 2: binary search in java
import java.util.Scanner;
class Main {
int binarySearch(int array[], int element, int low, int high) {
while (low <= high) {
int mid = low + (high - low) / 2;
if (array[mid] == element)
return mid;
if (array[mid] < element)
low = mid + 1;
else
high = mid - 1;
}
return -1;
}
public static void main(String args[]) {
Main obj = new Main();
int[] array = { 3, 4, 5, 6, 7, 8, 9 };
int n = array.length;
Scanner input = new Scanner(System.in);
System.out.println("Enter element to be searched:");
int element = input.nextInt();
input.close();
int result = obj.binarySearch(array, element, 0, n - 1);
if (result == -1)
System.out.println("Not found");
else
System.out.println("Element found at index " + result);
}
}