bubble sort linked list C code example
Example 1: sort linked list using bubble sort
void linked_list::sort ()
{
int i,j=0;
int counter=0;
node *curr=head;
node *trail=head;
node *temp=NULL;
while (curr !=NULL)
{
curr=curr->next; //couting the number of items I have in my list.
counter++; //this works fine.
}
curr=head->next; // reseting the curr value for the 2nd position.
for (i=0; i<counter; i++)
{
while (curr != NULL)
{
if (trail->data > curr->data)
{
temp=curr->next; //bubble sort for the pointers.
curr->next=trail;
trail->next=temp;
temp=curr; //reseting trail and curr. curr gets back to be infront.
curr=trail;
trail=temp;
if (j==0) //i'm using j to determine the start of the loop so i won't loose the head pointer.
{
head=trail;
}
}
j++;
trail=curr;
curr=curr->next; //traversing thru the list. nested loop.
}
trail=head;
curr=trail->next;
curr->next=trail->next->next; //traversing thru the list. outer loop.
j=0;
}
}
Example 2: bubble sort on a doubly linked list
public void sortList() {
Node current = null, index = null;
int temp;
//Check whether list is empty
if(head == null) {
return;
}
else {
//Current will point to head
for(current = head; current.next != null; current = current.next) {
//Index will point to node next to current
for(index = current.next; index != null; index = index.next) {
//If current's data is greater than index's data, swap the data of current and index
if(current.data > index.data) {
temp = current.data;
current.data = index.data;
index.data = temp;
}
}
}
}
}