Build a "BizzFuzz" program
Python, 114
a='Fizz'
b='Buzz'
c='Bizz'
d='Fuzz'
e=c+d
f=a+b
g=b+a
i=1
exec"print eval('ediifiiiaibiaiigiiic'[i%20]);i+=1;"*100
Original solution (131):
f='Fizz'
for i in range(1,101):x=i%20;print('Bizz'*(x%19<1)+'Fuzz'*(x<2)or(i%4<1)*f+'Buzz'*(i%5<1or x==4)+f*(x==15)or i,i)[x%11==5]
GolfScript (83 80 chars)
(NB Howard's suggestion in the comments allows to reduce to 78 chars, but with trailing spaces on some lines).
This uses the character \0, so here it is in xxd format:
0000000: 3130 302c 7b29 2e32 3025 2742 6946 750a 100,{).20%'BiFu.
0000010: 0046 750a 0000 0046 6942 750a 0000 0000 .Fu....FiBu.....
0000020: 4669 0a00 0042 750a 0000 4669 0a00 0000 Fi...Bu...Fi....
0000030: 4275 4669 0a00 0000 0042 690a 2731 2c2f BuFi.....Bi.'1,/
0000040: 3d32 2f27 7a7a 272a 5c6e 2b6f 727d 2f0a =2/'zz'*\n+or}/.
and base64:
MTAwLHspLjIwJSdCaUZ1CgBGdQoAAABGaUJ1CgAAAABGaQoAAEJ1CgAARmkKAAAAQnVGaQoAAAAA
QmkKJzEsLz0yLyd6eicqXG4rb3J9Lwo=
Using ^ as a stand-in for \0, it's
100,{).20%'BiFu
^Fu
^^^FiBu
^^^^Fi
^^Bu
^^Fi
^^^BuFi
^^^^Bi
'1,/=2/'zz'*\n+or}/
Still not a particularly interesting problem.
An explanation was requested:
For values 0 to 99 inclusive:
100,{
...
}/
Increment the value (we want 1 to 100) and also find out what the incremented value is mod 20:
).20%
Split the magic string around \0 characters:
MAGIC_STRING 1,/
Take the (x mod 20)th element of that array, split it into 2-character chunks, and glue them back together with zz. Note: the string is either empty (in which case there are no chunks, so we end up with the empty string) or is a sequence of [BF][iu] prefixes followed by a newline.
=2/'zz'*
Take the other copy of the incremented number which we kept on the stack, and append a newline. Now whichever string we keep will end with a newline.
\n+
Apply a fallback operation. (This is similar to || in JavaScript or COALESCE in SQL).
or
Python 2, 131
F,B,Z,I='Fizz','Buzz','Fuzz','Bizz'
for i in range(1,101):print{5:Z,19:I,i%4:B,i%5*4:F,3:B+F,16:F+B,0:I+Z,1:i,4:i}.get(i%4+i%5*4,i)