array with malloc in c code example

Example 1: c allocate array

int *array = malloc(10 * sizeof(int));

Example 2: allocate memory c

// Use malloc to allocate memory
ptr = (castType*) malloc(size);
int *exampl = (int*) malloc(sizeof(int));
// Use calloc to allocate and inizialize n contiguous blocks of memory
ptr = (castType*) calloc(n, size);
char *exampl = (char*) calloc(20, sizeof(char));

Example 3: malloc in c

#include <stdlib.h>

void *malloc(size_t size);

void exemple(void)
{
  char *string;
  
  string = malloc(sizeof(char) * 5);
  if (string == NULL)
    return;
  string[0] = 'H';
  string[1] = 'e';
  string[2] = 'y';
  string[3] = '!';
  string[4] = '\0';
  printf("%s\n", string);
  free(string);
}

/// output : "Hey!"

Example 4: n no of array in c using malloc

#include <stdio.h>

int main()
{
    printf("\n\n\t\tStudytonight - Best place to learn\n\n\n");
    int n, i, *ptr, sum = 0;

    printf("\n\nEnter number of elements: ");
    scanf("%d", &n);

    // dynamic memory allocation using malloc()
    ptr = (int *) malloc(n*sizeof(int));

    if(ptr == NULL) // if empty array
    {
        printf("\n\nError! Memory not allocated\n");
        return 0;   // end of program
    }

    printf("\n\nEnter elements of array: \n\n");
    for(i = 0; i < n; i++)
    {
        // storing elements at contiguous memory locations
        scanf("%d", ptr+i);    
        sum = sum + *(ptr + i);
    }

    // printing the array elements using pointer to the location
    printf("\n\nThe elements of the array are: ");
    for(i = 0; i < n; i++)
    {
        printf("%d  ",ptr[i]);    // ptr[i] is same as *(ptr + i)
    }

    /* 
        freeing memory of ptr allocated by malloc 
        using the free() method
    */
    free(ptr);

    printf("\n\n\t\t\tCoding is Fun !\n\n\n");
    return 0;
}