c++ binary search iterative code example
Example 1: binary search program c++
#include <iostream>
using namespace std;
int binarySearch(int array[], int size, int value)
{
int first = 0,
last = size - 1,
middle,
position = -1;
bool found = false;
while (!found && first <= last)
{
middle = (first + last) / 2;
if (array[middle] == value)
{
found = true;
position = middle;
}
else if (array[middle] > value)
last = middle - 1;
else
first = middle + 1;
}
return position;
}
int main ()
{
const int size = 5;
int array[size] = {1, 2, 3, 4, 5};
int value;
int result;
cout << "What value would you like to search for? ";
cin >> value;
result = binarySearch(array, size, value);
if (result == -1)
cout << "Not found\n";
else
cout << "Your value is in the array.\n";
return 0;
}
Example 2: binary search iterative
import java.io.*;
class Binary_Search
{
public static void main(String[] args) throws Exception
{
Binary_Search obj = new Binary_Search();
InputStreamReader isr = new InputStreamReader(System.in);
BufferedReader br = new BufferedReader(isr);
System.out.println("Insert the length of the Array : ");
int n = Integer.parseInt(br.readLine());
int arr[] = new int[n];
System.out.println("Insert elements into the array : ");
for(int i=0;i<n;i++)
{
arr[i] = Integer.parseInt(br.readLine());
}
System.out.println("Enter the num which you want to Search : ");
int num = Integer.parseInt(br.readLine());
obj.logic(arr,num);
}
void logic(int arr[],int num)
{
int r = arr.length - 1;
int l = 0;
int mid;
while(l<=r)
{
mid = l + (r-l)/2;
if(arr[mid] == num)
{
System.out.println("Number found at "+mid+"th index");
break;
}
else if(arr[mid]>num)
{
r = mid - 1;
}
else
{
l = mid + 1;
}
}
}
}