E. Copying Data using segment tree code example
Example 1: segmented trees
// C++ program to show segment tree operations like construction, query
// and update
#include <bits/stdc++.h>
using namespace std;
// A utility function to get the middle index from corner indexes.
int getMid(int s, int e) { return s + (e -s)/2; }
/* A recursive function to get the sum of values in the given range
of the array. The following are parameters for this function.
st --> Pointer to segment tree
si --> Index of current node in the segment tree. Initially
0 is passed as root is always at index 0
ss & se --> Starting and ending indexes of the segment represented
by current node, i.e., st[si]
qs & qe --> Starting and ending indexes of query range */
int getSumUtil(int *st, int ss, int se, int qs, int qe, int si)
{
// If segment of this node is a part of given range, then return
// the sum of the segment
if (qs <= ss && qe >= se)
return st[si];
// If segment of this node is outside the given range
if (se < qs || ss > qe)
return 0;
// If a part of this segment overlaps with the given range
int mid = getMid(ss, se);
return getSumUtil(st, ss, mid, qs, qe, 2*si+1) +
getSumUtil(st, mid+1, se, qs, qe, 2*si+2);
}
/* A recursive function to update the nodes which have the given
index in their range. The following are parameters
st, si, ss and se are same as getSumUtil()
i --> index of the element to be updated. This index is
in the input array.
diff --> Value to be added to all nodes which have i in range */
void updateValueUtil(int *st, int ss, int se, int i, int diff, int si)
{
// Base Case: If the input index lies outside the range of
// this segment
if (i < ss || i > se)
return;
// If the input index is in range of this node, then update
// the value of the node and its children
st[si] = st[si] + diff;
if (se != ss)
{
int mid = getMid(ss, se);
updateValueUtil(st, ss, mid, i, diff, 2*si + 1);
updateValueUtil(st, mid+1, se, i, diff, 2*si + 2);
}
}
// The function to update a value in input array and segment tree.
// It uses updateValueUtil() to update the value in segment tree
void updateValue(int arr[], int *st, int n, int i, int new_val)
{
// Check for erroneous input index
if (i < 0 || i > n-1)
{
cout<<"Invalid Input";
return;
}
// Get the difference between new value and old value
int diff = new_val - arr[i];
// Update the value in array
arr[i] = new_val;
// Update the values of nodes in segment tree
updateValueUtil(st, 0, n-1, i, diff, 0);
}
// Return sum of elements in range from index qs (quey start)
// to qe (query end). It mainly uses getSumUtil()
int getSum(int *st, int n, int qs, int qe)
{
// Check for erroneous input values
if (qs < 0 || qe > n-1 || qs > qe)
{
cout<<"Invalid Input";
return -1;
}
return getSumUtil(st, 0, n-1, qs, qe, 0);
}
// A recursive function that constructs Segment Tree for array[ss..se].
// si is index of current node in segment tree st
int constructSTUtil(int arr[], int ss, int se, int *st, int si)
{
// If there is one element in array, store it in current node of
// segment tree and return
if (ss == se)
{
st[si] = arr[ss];
return arr[ss];
}
// If there are more than one elements, then recur for left and
// right subtrees and store the sum of values in this node
int mid = getMid(ss, se);
st[si] = constructSTUtil(arr, ss, mid, st, si*2+1) +
constructSTUtil(arr, mid+1, se, st, si*2+2);
return st[si];
}
/* Function to construct segment tree from given array. This function
allocates memory for segment tree and calls constructSTUtil() to
fill the allocated memory */
int *constructST(int arr[], int n)
{
// Allocate memory for the segment tree
//Height of segment tree
int x = (int)(ceil(log2(n)));
//Maximum size of segment tree
int max_size = 2*(int)pow(2, x) - 1;
// Allocate memory
int *st = new int[max_size];
// Fill the allocated memory st
constructSTUtil(arr, 0, n-1, st, 0);
// Return the constructed segment tree
return st;
}
// Driver program to test above functions
int main()
{
int arr[] = {1, 3, 5, 7, 9, 11};
int n = sizeof(arr)/sizeof(arr[0]);
// Build segment tree from given array
int *st = constructST(arr, n);
// Print sum of values in array from index 1 to 3
cout<<"Sum of values in given range = "<<getSum(st, n, 1, 3)<<endl;
// Update: set arr[1] = 10 and update corresponding
// segment tree nodes
updateValue(arr, st, n, 1, 10);
// Find sum after the value is updated
cout<<"Updated sum of values in given range = "
<<getSum(st, n, 1, 3)<<endl;
return 0;
}
//This code is contributed by rathbhupendra
Example 2: segment tree complexity
class SegmentTree{
public:
vector<int> segv;
int n;
SegmentTree(vector<int> &nums) {
if (!nums.size()) return ;
segv.assign(nums.size() * 4, 0);
n = nums.size();
build(nums, 1, 0, n - 1);
}
void build(vector<int> &nums, int v, int l, int r) {
if (l == r) segv[v] = nums[l];
else {
int mid = l + (r - l) / 2;
build(nums, v * 2, l, mid);
build(nums, v * 2 + 1, mid + 1, r);
segv[v] = segv[v * 2] + segv[v * 2 + 1];
}
}
int sumRange(int v, int l, int r, int a, int b) {
if (a > b) return 0;
if (l == a && r == b) return segv[v];
int mid = l + (r - l) / 2;
return sumRange(v * 2, l, mid, a, min(mid, b))
+ sumRange(v * 2 + 1, mid + 1, r, max(mid + 1, a), b);
}
void update(int v, int l, int r, int pos, int val) {
if (l == r) segv[v] = val;
else {
int mid = l + (r - l) / 2;
if (pos <= mid) update(v * 2, l, mid, pos, val);
else update(v * 2 + 1, mid + 1, r, pos, val);
segv[v] = segv[v * 2] + segv[v * 2 + 1];
}
}
int sumRange(int a, int b) {
return sumRange(1, 0, n - 1, a, b);
}
void update(int pos, int val) {
update(1, 0, n - 1, pos, val);
}
};