efficient way to check an array for no duplicates in java code example

Example 1: java find duplicates in array

package dto;

import java.util.HashMap;
import java.util.HashSet;
import java.util.Map;
import java.util.Map.Entry;
import java.util.Set;

/**
 * Java Program to find duplicate elements in an array. There are two straight
 * forward solution of this problem first, brute force way and second by using
 * HashSet data structure. A third solution, similar to second one is by using
 * hash table data structure e.g. HashMap to store count of each element and
 * print element with count 1.
 * 
 * @author java67
 */

public class DuplicatesInArray{

    public static void main(String args[]) {

        String[] names = { "Java", "JavaScript", "Python", "C", "Ruby", "Java" };

        // First solution : finding duplicates using brute force method
        System.out.println("Finding duplicate elements in array using brute force method");
        for (int i = 0; i < names.length; i++) {
            for (int j = i + 1; j < names.length; j++) {
                if (names[i].equals(names[j]) ) {
                   // got the duplicate element
                }
            }
        }

        // Second solution : use HashSet data structure to find duplicates
        System.out.println("Duplicate elements from array using HashSet data structure");
        Set<String> store = new HashSet<>();

        for (String name : names) {
            if (store.add(name) == false) {
                System.out.println("found a duplicate element in array : "
                        + name);
            }
        }

        // Third solution : using Hash table data structure to find duplicates
        System.out.println("Duplicate elements from array using hash table");
        Map<String, Integer> nameAndCount = new HashMap<>();

        // build hash table with count
        for (String name : names) {
            Integer count = nameAndCount.get(name);
            if (count == null) {
                nameAndCount.put(name, 1);
            } else {
                nameAndCount.put(name, ++count);
            }
        }

        // Print duplicate elements from array in Java
        Set<Entry<String, Integer>> entrySet = nameAndCount.entrySet();
        for (Entry<String, Integer> entry : entrySet) {

            if (entry.getValue() > 1) {
                System.out.println("Duplicate element from array : "
                        + entry.getKey());
            }
        }
    }
}
Output :
Finding duplicate elements in array using brute force method
Duplicate elements from array using HashSet data structure
found a duplicate element in array : Java
Duplicate elements from array using hash table
Duplicate element from array : Java

Example 2: find-array-duplicates

npm i find-array-duplicates

import duplicates from 'find-array-duplicates'

const names = [
 { 'age': 36, 'name': 'Bob' },
 { 'age': 40, 'name': 'Harry' },
 { 'age': 1,  'name': 'Bob' }
]
 
duplicates(names, 'name').single()
// => { 'age': 36, 'name': 'Bob' }

Example 3: java find duplicates in array

// Uses a set, which does not allow duplicates 

for (String name : names) 
{
     if (set.add(name) == false) 
     {
        // print name your duplicate element
     }
}