C++ getters/setters coding style

As an aside, in C++, it is somewhat odd to have a const reference member. You have to assign it in the constructor list. Who owns the actually memory of that object and what is it's lifetime?

As for style, I agree with the others that you don't want to expose your privates. :-) I like this pattern for setters/getters

class Foo
{
public:
  const string& FirstName() const;
  Foo& FirstName(const string& newFirstName);

  const string& LastName() const;
  Foo& LastName(const string& newLastName);

  const string& Title() const;
  Foo& Title(const string& newTitle);
};

This way you can do something like:

Foo f;
f.FirstName("Jim").LastName("Bob").Title("Programmer");

I think the C++11 approach would be more like this now.

#include <string>
#include <iostream>
#include <functional>

template<typename T>
class LambdaSetter {
public:
    LambdaSetter() :
        getter([&]() -> T { return m_value; }),
        setter([&](T value) { m_value = value; }),
        m_value()
    {}

    T operator()() { return getter(); }
    void operator()(T value) { setter(value); }

    LambdaSetter operator=(T rhs)
    {
        setter(rhs);
        return *this;
    }

    T operator=(LambdaSetter rhs)
    {
        return rhs.getter();
    }

    operator T()
    { 
        return getter();
    }


    void SetGetter(std::function<T()> func) { getter = func; }
    void SetSetter(std::function<void(T)> func) { setter = func; }

    T& GetRawData() { return m_value; }

private:
    T m_value;
    std::function<const T()> getter;
    std::function<void(T)> setter;

    template <typename TT>
    friend std::ostream & operator<<(std::ostream &os, const LambdaSetter<TT>& p);

    template <typename TT>
    friend std::istream & operator>>(std::istream &is, const LambdaSetter<TT>& p);
};

template <typename T>
std::ostream & operator<<(std::ostream &os, const LambdaSetter<T>& p)
{
    os << p.getter();
    return os;
}

template <typename TT>
std::istream & operator>>(std::istream &is, const LambdaSetter<TT>& p)
{
    TT value;
    is >> value;
    p.setter(value);
    return is;
}


class foo {
public:
    foo()
    {
        myString.SetGetter([&]() -> std::string { 
            myString.GetRawData() = "Hello";
            return myString.GetRawData();
        });
        myString2.SetSetter([&](std::string value) -> void { 
            myString2.GetRawData() = (value + "!"); 
        });
    }


    LambdaSetter<std::string> myString;
    LambdaSetter<std::string> myString2;
};

int _tmain(int argc, _TCHAR* argv[])
{
    foo f;
    std::string hi = f.myString;

    f.myString2 = "world";

    std::cout << hi << " " << f.myString2 << std::endl;

    std::cin >> f.myString2;

    std::cout << hi << " " << f.myString2 << std::endl;

    return 0;
}

I tested this in Visual Studio 2013. Unfortunately in order to use the underlying storage inside the LambdaSetter I needed to provide a "GetRawData" public accessor which can lead to broken encapsulation, but you can either leave it out and provide your own storage container for T or just ensure that the only time you use "GetRawData" is when you are writing a custom getter/setter method.

Using a getter method is a better design choice for a long-lived class as it allows you to replace the getter method with something more complicated in the future. Although this seems less likely to be needed for a const value, the cost is low and the possible benefits are large.

As an aside, in C++, it's an especially good idea to give both the getter and setter for a member the same name, since in the future you can then actually change the the pair of methods:

class Foo {
public:
    std::string const& name() const;          // Getter
    void name(std::string const& newName);    // Setter
    ...
};

Into a single, public member variable that defines an operator()() for each:

// This class encapsulates a fancier type of name
class fancy_name {
public:
    // Getter
    std::string const& operator()() const {
        return _compute_fancy_name();    // Does some internal work
    }

    // Setter
    void operator()(std::string const& newName) {
        _set_fancy_name(newName);        // Does some internal work
    }
    ...
};

class Foo {
public:
    fancy_name name;
    ...
};

The client code will need to be recompiled of course, but no syntax changes are required! Obviously, this transformation works just as well for const values, in which only a getter is needed.

It tends to be a bad idea to make non-const fields public because it then becomes hard to force error checking constraints and/or add side-effects to value changes in the future.

In your case, you have a const field, so the above issues are not a problem. The main downside of making it a public field is that you're locking down the underlying implementation. For example, if in the future you wanted to change the internal representation to a C-string or a Unicode string, or something else, then you'd break all the client code. With a getter, you could convert to the legacy representation for existing clients while providing the newer functionality to new users via a new getter.

I'd still suggest having a getter method like the one you have placed above. This will maximize your future flexibility.