How do you find the duplicate number on a given integer array c++ code example
Example 1: find duplicate in an array using xor
int DuplicateNumber(int arr[], int size){
int ans=0;
for(int i=0;i<size;i++){
ans= ans ^ arr[i] ;
}
for(int i=0;i<=size-2;i++){
ans= ans ^ i;
}
return ans;
}
Example 2: find duplicate elements in array in java
public static void findDuplicateArray(int [] array)
{
int size = array.length;
int [] countFrequency = new int[size];
for(int i = 0; i < size; i++)
{
countFrequency[i] = -1;
}
int count = 1;
for(int i = 0; i < size; i++)
{
if(countFrequency[i] != 0)
{
for(int j = i+1; j < size; j++)
{
if(array[i] == array[j])
{
count++;
countFrequency[j]= 0;
}
}
countFrequency[i] = count;
}
count = 1;
}
System.out.println("array without duplicate elements");
for(int i = 0; i < array.length; i++)
{
if(countFrequency[i] >= 1)
System.out.print(array[i] + " ");
}
System.out.println();
System.out.println("duplicate elements in array");
for(int i = 0; i < array.length; i++)
{
if(countFrequency[i]/2 >= 1)
System.out.print(array[i] + " ");
}
System.out.println();
System.out.println("number of duplicate elements");
count = 0;
for(int i = 0; i < array.length; i++)
{
if(countFrequency[i]/2 >= 1)
count++;
}
System.out.print(count);
System.out.println();
System.out.println("numbers of pair of dulicate with repeatation");
count = 0;
for(int i = 0; i < array.length; i++)
{
if(countFrequency[i] >= 2)
{
int div = countFrequency[i]/2;
count+=div;
}
}
System.out.println(count);
int [] array3 = new int [array.length];
for(int i = 0; i < array.length; i++)
{
for(int j = 0; j < countFrequency[i]; j++)
{
array3[i]= array[i];
}
}
}