how to display the single linked list in c code example
Example: creating and displaying linked list in c
#include <stdio.h>
#include <stdlib.h>
struct node
{
int num;
struct node *nextptr;
}*stnode;
void createNodeList(int n);
void displayList();
int main()
{
int n;
printf("\n\n Linked List : To create and display Singly Linked List :\n");
printf("-------------------------------------------------------------\n");
printf(" Input the number of nodes : ");
scanf("%d", &n);
createNodeList(n);
printf("\n Data entered in the list : \n");
displayList();
return 0;
}
void createNodeList(int n)
{
struct node *fnNode, *tmp;
int num, i;
stnode = (struct node *)malloc(sizeof(struct node));
if(stnode == NULL)
{
printf(" Memory can not be allocated.");
}
else
{
printf(" Input data for node 1 : ");
scanf("%d", &num);
stnode->num = num;
stnode->nextptr = NULL;
tmp = stnode;
for(i=2; i<=n; i++)
{
fnNode = (struct node *)malloc(sizeof(struct node));
if(fnNode == NULL)
{
printf(" Memory can not be allocated.");
break;
}
else
{
printf(" Input data for node %d : ", i);
scanf(" %d", &num);
fnNode->num = num;
fnNode->nextptr = NULL;
tmp->nextptr = fnNode;
tmp = tmp->nextptr;
}
}
}
}
void displayList()
{
struct node *tmp;
if(stnode == NULL)
{
printf(" List is empty.");
}
else
{
tmp = stnode;
while(tmp != NULL)
{
printf(" Data = %d\n", tmp->num);
tmp = tmp->nextptr;
}
}
}