how to find maximum element in an array in c++ code example

Example 1: how to get the largest number in a c++ array

#include <iostream>
using namespace std;
int main(){
   //n is the number of elements in the array
   int n, largest;
   int num[50];
   cout<<"Enter number of elements you want to enter: ";
   cin>>n;
   
   /* Loop runs from o to n, in such a way that first
    * element entered by user is stored in num[0], second 
    * in num[1] and so on. 
    */
   for(int i = 0; i < n; i++) {
      cout<<"Enter Element "<<(i+1)<< ": ";
      cin>>num[i];
   }
   // Storing first array element in "largest" variable
   largest = num[0];
   for(int i = 1;i < n; i++) {
      /* We are comparing largest variable with every element
       * of array. If there is an element which is greater than
       * largest variable value then we are copying that variable
       * to largest, this way we have the largest element copied
       * to the variable named "largest" at the end of the loop 
       *
       */
      if(largest < num[i])
         largest = num[i];
   } 
   cout<<"Largest element in array is: "<<largest;
   return 0;
}

Example 2: c++ max of array

cout << " max element is: " << *max_element(array , array + n) << endl;

Example 3: find the maximum number from an int Array

---without sort method---
public static int maxValue( int[]  n ) {

int max = Integer.MIN_VALUE;

for(int each: n)

if(each > max)

max = each;

 
return max;
  
---with sort method---
public static int maxValue( int[]  n ) {

Arrays.sort( n );

return  n [ n.lenth-1 ];

}

Example 4: maximum int c++

#include <limits>

int imin = std::numeric_limits<int>::min(); // minimum value
int imax = std::numeric_limits<int>::max(); // maximum value (2147483647)

Example 5: max element in array

int max;
max=INT_MIN;

for(int i=0;i<ar.length();i++){
	if(ar[i]>max){
    	max=ar[i];
    }