how to slice a dataframe by column index code example

Example 1: dataframe slice by list of values

In [1]: df = pd.DataFrame({'A': [5,6,3,4], 'B': [1,2,3,5]})

In [2]: df
Out[2]:
   A  B
0  5  1
1  6  2
2  3  3
3  4  5

In [3]: df[df['A'].isin([3, 6])]
Out[3]:
   A  B
1  6  2
2  3  3

Example 2: python - row slice dataframe by number of rows

df.iloc[[1, 5]]                                               # Get rows 1 and 5
df.iloc[1:6]                                                  # Get rows 1 to 5 inclusive
df.iloc[[1, 5], df.columns.get_loc('Shop')]                   # Get only specific column
df.iloc[[1, 5], df.columns.get_indexer(['Shop', 'Category'])] # Get multiple columns

Example 3: pandas df by row index

indices = [133, 22, 19, 203, 14, 1]
df_by_indices = df.iloc[indices, :]

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