how to use linked list in python code example

Example 1: linked list in python

class Node:
    def __init__(self, data = None, next_node = None):
        self.data = data
        self.nextNode = next_node

    def get_data(self):
        return self.data

    def set_data(self, data):
        self.data = data

    def get_nextNode(self):
        return self.nextNode

    def set_nextNode(self, nextNode):
        self.nextNode = nextNode


class LinkedList:
    def __init__(self, head = None):
        self.head = head


    def add_Node(self, data):
        # if empty
        if self.head == None:
            self.head = Node(data)


        # not empty
        else:
            curr_Node = self.head
            
            # if node added is at the start
            if data < curr_Node.get_data():
                self.head = Node(data, curr_Node)
                
            # not at start
            else:
                while data > curr_Node.get_data() and curr_Node.get_nextNode() != None:
                    prev_Node = curr_Node
                    curr_Node = curr_Node.get_nextNode()

                # if node added is at the middle
                if data < curr_Node.get_data():
                    prev_Node.set_nextNode(Node(data, curr_Node))
                

                # if node added is at the last
                elif data > curr_Node.get_data() and curr_Node.get_nextNode() == None:
                    curr_Node.set_nextNode(Node(data))



    def search(self, data):
        curr_Node = self.head
        while curr_Node != None:
            if data == curr_Node.get_data():
                return True

            else:
                curr_Node = curr_Node.get_nextNode()

        return False


    def delete_Node(self, data):
        if self.search(data):
            # if data is found

            curr_Node = self.head
            #if node to be deleted is the first node
            if curr_Node.get_data() == data:
                self.head = curr_Node.get_nextNode()

            else:
                while curr_Node.get_data() != data:
                    prev_Node = curr_Node
                    curr_Node = curr_Node.get_nextNode()
                    
                #node to be deleted is middle
                if curr_Node.get_nextNode() != None:
                    prev_Node.set_nextNode(curr_Node.get_nextNode())

                # node to be deleted is at the end
                elif curr_Node.get_nextNode() == None:
                    prev_Node.set_nextNode(None)

        else:
            return "Not found."

    def return_as_lst(self):
        lst = []
        curr_Node = self.head
        while curr_Node != None:
            lst.append(curr_Node.get_data())
            curr_Node = curr_Node.get_nextNode()

        return lst

    def size(self):
        curr_Node = self.head
        count = 0
        while curr_Node:
            count += 1
            curr_Node = curr_Node.get_nextNode()
        return count

      
## TEST CASES #
test1 = LinkedList()
test2 = LinkedList()
test1.add_Node(20)
test1.add_Node(15)
test1.add_Node(13)
test1.add_Node(14)
test1.delete_Node(17)
print(test1.return_as_lst())
print(test2.size())

Example 2: linked list python

class Node:
    def __init__(self, val):
        self.val = val
        self.next = None
    
    def nexts(self, nexts):
        self.next = nexts
        
        
    def __repr__(self):
        return f'{self.val} -> {self.next} '
      
      
class LinkedList:
    def __init__(self):
        self.head = None
    
    def add(self, val):
        if self.head == None:
            self.head = val
        else:
            val.next = self.head
            self.head = val
    
    def __repr__(self):
        return self.head.__repr__()
    
    def __iter__(self):
        li = self.head
        while  li.next != None:
            yield li.val
            li = li.next
        yield li.val
    
    def  __getitem__(self, n):
        if n==0: return self.head.val
        li = self.head
        for i in range(n):
            li = li.next
        return li.val
    
    def __len__(self):
        for i,v in enumerate(self):
            pass
        return i+1