int* arr = new int[5]; for (int i = 0; i < 5; i++) *arr = i * 2; for (int j = 0; j < 5; j++) cout << *arr << " "; code example

Example: #include int main() { int n; scanf("%d",&n); int ar[n]; int count=0; for(int i=0;i whatever by Agreeable Ant on May 07 2020 Donate Comment

#include<stdio.h>
int main()
{
	int n;
	scanf("%d",&n);
	int ar[n];
	int count=0;
	for(int i=0;i<n;i++)
	{
		scanf("%d",&ar[i]);
	}
	for(int i=0;i<n;i++)
	{
		for(int j=0;j<n;j++)
		{
			if(ar[i]==ar[j])
			{
				count=count+1;
			}
			else
			{
				count=0;
			}
		}
	}
printf("%d\n",(count)/2);	
}

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C Example