c++ program to print odd numbers from 1 to 100 code example

Example 1: return odd numbers c++ for loop

#include<iostream>
int copyOdd (int A[], int sizeA, int B[]);



int main ()
{
    int arr [] {1,2,3,4,5,6,7,8,9,10};
    int Odd [5] {0,0,0,0,0};
    copyOdd(arr,9,Odd);
    

    for(int i = 0 ; i < 5; ++i)
    {
        std::cout<<Odd[i]<<' ';
    }
    std::cout<<std::endl;

    return 0 ;

}

int copyOdd (int A[], int sizeA, int B[])
{   
    int j {0};
    B [5];
    for(int i  = 0 ; i < sizeA ; ++i)
    {
        if(A[i]%2 == 1)
            B[j++] = A[i];
            
    }

    return B[5];
}

Example 2: c++ sum of even and odd numbers

//given the fact that it takes n of number
void sumEvenAndOdd(){
int n=0 , evenSum=0 , oddSum=0;
     int numbers[Size];
     cout<<"enters the number(N) of integers\n";
     cin>>Size;

     cout<<"Enter "<<Size<<" number/s:\n";
     for(int i =0 ;i< Size ; ++i){
        cin>>numbers[i];
     }
     for(int i =0 ;i<Size ; ++i){
        if(numbers[i]%2 ==0){
            evenSum += numbers[i];
        }
        else{
            oddSum += numbers[i];
        }
     }
     cout<<"the sum of even numbers is : "<<evenSum <<"\nthe sum of odd numbers is :"<<oddSum<<endl;
}