c# regex matches example

So you're trying to grab numeric values that are preceded by the token "%download%#"?

Try this pattern:

(?<=%download%#)\d+

That should work. I don't think # or % are special characters in .NET Regex, but you'll have to either escape the backslash like \\ or use a verbatim string for the whole pattern:

var regex = new Regex(@"(?<=%download%#)\d+");
return regex.Matches(strInput);

Tested here: http://rextester.com/BLYCC16700

NOTE: The lookbehind assertion (?<=...) is important because you don't want to include %download%# in your results, only the numbers after it. However, your example appears to require it before each string you want to capture. The lookbehind group will make sure it's there in the input string, but won't include it in the returned results. More on lookaround assertions here.

All the other responses I see are fine, but C# has support for named groups!

I'd use the following code:

const string input = "Lorem ipsum dolor sit %download%#456 amet, consectetur adipiscing %download%#3434 elit. Duis non nunc nec mauris feugiat porttitor. Sed tincidunt blandit dui a viverra%download%#298. Aenean dapibus nisl %download%#893434 id nibh auctor vel tempor velit blandit.";

static void Main(string[] args)
{
    Regex expression = new Regex(@"%download%#(?<Identifier>[0-9]*)");
    var results = expression.Matches(input);
    foreach (Match match in results)
    {
        Console.WriteLine(match.Groups["Identifier"].Value);
    }
}

The code that reads: (?<Identifier>[0-9]*) specifies that [0-9]*'s results will be part of a named group that we index as above: match.Groups["Identifier"].Value

    public void match2()
    {
        string input = "%download%#893434";
        Regex word = new Regex(@"\d+");
        Match m = word.Match(input);
        Console.WriteLine(m.Value);
    }