round robin coding problem code example
Example: round robin algorithm in c
#include<stdio.h>
int main()
{
int i, limit, total = 0, x, counter = 0, time_quantum;
int wait_time = 0, turnaround_time = 0, arrival_time[10], burst_time[10], temp[10];
float average_wait_time, average_turnaround_time;
printf("nEnter Total Number of Processes:t");
scanf("%d", &limit);
x = limit;
for(i = 0; i < limit; i++)
{
printf("nEnter Details of Process[%d]n", i + 1);
printf("Arrival Time:t");
scanf("%d", &arrival_time[i]);
printf("Burst Time:t");
scanf("%d", &burst_time[i]);
temp[i] = burst_time[i];
}
printf("nEnter Time Quantum:t");
scanf("%d", &time_quantum);
printf("nProcess IDttBurst Timet Turnaround Timet Waiting Timen");
for(total = 0, i = 0; x != 0;)
{
if(temp[i] <= time_quantum && temp[i] > 0)
{
total = total + temp[i];
temp[i] = 0;
counter = 1;
}
else if(temp[i] > 0)
{
temp[i] = temp[i] - time_quantum;
total = total + time_quantum;
}
if(temp[i] == 0 && counter == 1)
{
x--;
printf("nProcess[%d]tt%dtt %dttt %d", i + 1, burst_time[i], total - arrival_time[i], total - arrival_time[i] - burst_time[i]);
wait_time = wait_time + total - arrival_time[i] - burst_time[i];
turnaround_time = turnaround_time + total - arrival_time[i];
counter = 0;
}
if(i == limit - 1)
{
i = 0;
}
else if(arrival_time[i + 1] <= total)
{
i++;
}
else
{
i = 0;
}
}
average_wait_time = wait_time * 1.0 / limit;
average_turnaround_time = turnaround_time * 1.0 / limit;
printf("nnAverage Waiting Time:t%f", average_wait_time);
printf("nAvg Turnaround Time:t%fn", average_turnaround_time);
return 0;
}