c++ std::enable_if .... else?

What you are looking for is constexpr if. That will let you write the code like

template<typename Obj>
void run(Obj o)
{
    if constexpr (std::is_function_v<std::remove_pointer_t<Obj>>)
        o();
    else
        o.print();
}

^{Live Example}

If you don't have access to C++17 but do have C++14, you can at least shorten the code you need to write using a variable template. That would look like

template<typename T>
static constexpr bool is_function_v = std::is_function< typename std::remove_pointer<T>::type >::value;

template<typename Function>
typename std::enable_if< is_function_v<Function>, void>::type 
run(Function f)
{
    f();
}


template<typename T>
typename std::enable_if< !is_function_v<T>, void>::type 
run(T& t)
{
    t.print();
}

^{Live Example}

You can use the tag dispatch mechanism if you are limited to using C++11.

namespace detail
{
   template<typename Function>
   void run(std::true_type, Function& f)
   {
      f();
   }

   template<typename Object>
   void run(std::false_type, Object& o)
   {
      o.print();
   }

} // namespace detail

template<typename T>
void run(T& t)
{
   constexpr bool t_is_a_function = 
      std::is_function<typename std::remove_pointer<T>::type >::value;
   using tag = std::integral_constant<bool, t_is_a_function>;
   detail::run(tag{}, t);
}

Working example.