Write a program to accept 10 integers in an array and for each one of them, separately, indicate the number of even digits, odd digits, and total number of digits code example

Example 1: Print Odd Even Negative Integer Count

#include<stdio.h>
int main()
{
int n,i,e=0,o=0,ne=0;
scanf("%d",&n);
int a[n];
for(i=0;i<n;i++){
    scanf("%d",&a[i]);
if(a[i]<0) ne++;
else if(a[i]%2==0&&a[i]>=0) e++;
else o++;
}
    printf("%d %d %d",o,e,ne);

}

Example 2: Print Odd Even Negative Integer Count

n,neg,odd,eve,m=int(input()),0,0,0,[int(i) for i in input().split()]
for i in m:
    if i<0:
        neg+=1
    elif i%2==0 :
        eve+=1
    else:
        odd+=1
print("{0} {1} {2}".format(odd,eve,neg))