Calculate point based on distance and direction
A 2020 update for this question, based on Dr. Jan-Philip Gehrcke's answer.
VincentyDistance
is officially deprecated, and was never fully precise and sometimes inaccurate.
This snippet shows how to use with the latest (and future versions of GeoPy - Vincenty will be deprecated in 2.0)
import geopy
import geopy.distance
# Define starting point.
start = geopy.Point(48.853, 2.349)
# Define a general distance object, initialized with a distance of 1 km.
d = geopy.distance.distance(kilometers=1)
# Use the `destination` method with a bearing of 0 degrees (which is north)
# in order to go from point `start` 1 km to north.
final = d.destination(point=start, bearing=0)
final
is a new Point
object, which when printed, returns 48 51m 43.1721s N, 2 20m 56.4s E
Which as you can see is more accurate than Vincenty
, and should maintain better accuracy near the poles.
Hope it helps!
Edit 2
Okay, there is an out-of-the-box solution with geopy, it is just not well-documented:
import geopy
import geopy.distance
# Define starting point.
start = geopy.Point(48.853, 2.349)
# Define a general distance object, initialized with a distance of 1 km.
d = geopy.distance.VincentyDistance(kilometers = 1)
# Use the `destination` method with a bearing of 0 degrees (which is north)
# in order to go from point `start` 1 km to north.
print d.destination(point=start, bearing=0)
The output is 48 52m 0.0s N, 2 21m 0.0s E
(or Point(48.861992239749355, 2.349, 0.0)
).
A bearing of 90 degrees corresponds to East, 180 degrees is South, and so on.
Older answers:
A simple solution would be:
def get_new_point():
# After going 1 km North, 1 km East, 1 km South and 1 km West
# we are back where we were before.
return (-24680.1613, 6708860.65389)
However, I am not sure if that serves your purposes in all generality.
Okay, seriously, you can get started using geopy. First of all, you need to define your starting point in a coordinate system known to geopy. At the first glance, it seems that you cannot just "add" a certain distance into a certain direction. The reason, I think, is that calculation of the distance is a problem without simple inverse solution. Or how would we invert the measure
function defined in https://code.google.com/p/geopy/source/browse/trunk/geopy/distance.py#217?
Hence, you might want to take an iterative approach.
As stated here: https://stackoverflow.com/a/9078861/145400 you can calculate the distance between two given points like that:
pt1 = geopy.Point(48.853, 2.349)
pt2 = geopy.Point(52.516, 13.378)
# distance.distance() is the VincentyDistance by default.
dist = geopy.distance.distance(pt1, pt2).km
For going north by one kilometer you would iteratively change the latitude into a positive direction and check against the distance. You can automate this approach using a simple iterative solver from e.g. SciPy: just find the root of geopy.distance.distance().km - 1
via one of the optimizers listed in http://docs.scipy.org/doc/scipy/reference/optimize.html#root-finding.
I think it is clear that you go south by changing the latitude into a negative direction, and west and east by changing the longitude.
I have no experience with such geo calculations, this iterative approach only makes sense if there is no simple direct way for "going north" by a certain distance.
Edit: an example implementation of my proposal:
import geopy
import geopy.distance
import scipy.optimize
def north(startpoint, distance_km):
"""Return target function whose argument is a positive latitude
change (in degrees) relative to `startpoint`, and that has a root
for a latitude offset that corresponds to a point that is
`distance_km` kilometers away from the start point.
"""
def target(latitude_positive_offset):
return geopy.distance.distance(
startpoint, geopy.Point(
latitude=startpoint.latitude + latitude_positive_offset,
longitude=startpoint.longitude)
).km - distance_km
return target
start = geopy.Point(48.853, 2.349)
print "Start: %s" % start
# Find the root of the target function, vary the positve latitude offset between
# 0 and 2 degrees (which is for sure enough for finding a 1 km distance, but must
# be adjusted for larger distances).
latitude_positive_offset = scipy.optimize.bisect(north(start, 1), 0, 2)
# Build Point object for identified point in space.
end = geopy.Point(
latitude=start.latitude + latitude_positive_offset,
longitude=start.longitude
)
print "1 km north: %s" % end
# Make the control.
print "Control distance between both points: %.4f km." % (
geopy.distance.distance(start, end).km)
Output:
$ python test.py
Start: 48 51m 0.0s N, 2 21m 0.0s E
1 km north: 48 52m 0.0s N, 2 21m 0.0s E
Control distance between both points: 1.0000 km.