Calling a function of a module by using its name (a string)
Given a module foo
with method bar
:
import foo
bar = getattr(foo, 'bar')
result = bar()
getattr
can similarly be used on class instance bound methods, module-level methods, class methods... the list goes on.
Just a simple contribution. If the class that we need to instance is in the same file, we can use something like this:
# Get class from globals and create an instance
m = globals()['our_class']()
# Get the function (from the instance) that we need to call
func = getattr(m, 'function_name')
# Call it
func()
For example:
class A:
def __init__(self):
pass
def sampleFunc(self, arg):
print('you called sampleFunc({})'.format(arg))
m = globals()['A']()
func = getattr(m, 'sampleFunc')
func('sample arg')
# Sample, all on one line
getattr(globals()['A'](), 'sampleFunc')('sample arg')
And, if not a class:
def sampleFunc(arg):
print('you called sampleFunc({})'.format(arg))
globals()['sampleFunc']('sample arg')
Based on Patrick's solution, to get the module dynamically as well, import it using:
module = __import__('foo')
func = getattr(module, 'bar')
func()
Using
locals()
, which returns a dictionary with the current local symbol table:locals()["myfunction"]()
Using
globals()
, which returns a dictionary with the global symbol table:globals()["myfunction"]()