Can a line of Python code know its indentation nesting level?
If you want indentation in terms of nesting level rather than spaces and tabs, things get tricky. For example, in the following code:
if True:
print(
get_nesting_level())
the call to get_nesting_level
is actually nested one level deep, despite the fact that there is no leading whitespace on the line of the get_nesting_level
call. Meanwhile, in the following code:
print(1,
2,
get_nesting_level())
the call to get_nesting_level
is nested zero levels deep, despite the presence of leading whitespace on its line.
In the following code:
if True:
if True:
print(get_nesting_level())
if True:
print(get_nesting_level())
the two calls to get_nesting_level
are at different nesting levels, despite the fact that the leading whitespace is identical.
In the following code:
if True: print(get_nesting_level())
is that nested zero levels, or one? In terms of INDENT
and DEDENT
tokens in the formal grammar, it's zero levels deep, but you might not feel the same way.
If you want to do this, you're going to have to tokenize the whole file up to the point of the call and count INDENT
and DEDENT
tokens. The tokenize
module would be very useful for such a function:
import inspect
import tokenize
def get_nesting_level():
caller_frame = inspect.currentframe().f_back
filename, caller_lineno, _, _, _ = inspect.getframeinfo(caller_frame)
with open(filename) as f:
indentation_level = 0
for token_record in tokenize.generate_tokens(f.readline):
token_type, _, (token_lineno, _), _, _ = token_record
if token_lineno > caller_lineno:
break
elif token_type == tokenize.INDENT:
indentation_level += 1
elif token_type == tokenize.DEDENT:
indentation_level -= 1
return indentation_level
Yeah, that's definitely possible, here's a working example:
import inspect
def get_indentation_level():
callerframerecord = inspect.stack()[1]
frame = callerframerecord[0]
info = inspect.getframeinfo(frame)
cc = info.code_context[0]
return len(cc) - len(cc.lstrip())
if 1:
print get_indentation_level()
if 1:
print get_indentation_level()
if 1:
print get_indentation_level()