Can you combine the raw string modifier R"()" with a string variable?
Is there a way to append the raw string modifier to a variable containing a string in order to print the raw form of the string contained within the variable?
No.
However, you can write a function that substitutes the characters that are defined by escape sequences by an appropriate string, i.e. replace the character '\t'
by the string "\\t"
.
Sample program:
#include <iostream>
#include <string>
// Performs only one substitution of \t.
// Needs to be updated to do it for all occurrences of \t and
// all other escape sequences that can be found in raw strings.
std::string toRawString(std::string const& in)
{
std::string ret = in;
auto p = ret.find('\t');
if ( p != ret.npos )
{
ret.replace(p, 1, "\\t");
}
return ret;
}
int main()
{
std::string TestString = "Test\tString";
std::cout << toRawString(TestString) << std::endl;
}
Output:
Test\tString
This question is tagged as C++11, in which case rolling your own conversion function is probably the best call.
However, if you have a C++14 compiler, you can use the std::quoted
stream manipulator:
#include <iostream>
#include <iomanip>
int main() {
string s = "Hello\tWorld!";
std::cout << std::quoted(s) << std::endl; // Prints "Hello\tWorld!"
}