Ceil and floor equivalent in Python 3 without Math module?

I know this is old...but you can call those like this too:

>>> (3/2).__ceil__()
2
>>> (3/2).__floor__()
1

edit: this is for python 3.9 and above

Try:

def ceil(n):
    res = int(n)
    return res if res == n or n < 0 else res+1

def floor(n):
    res = int(n)
    return res if res == n or n >= 0 else res-1

Try

def ceil(n):
    return int(-1 * n // 1 * -1)

def floor(n):
    return int(n // 1)

I used int() to make the values integer. As ceiling and floor are a type of rounding, I thought integer is the appropriate type to return.

The integer division //, goes to the next whole number to the left on the number line. Therefore by using -1, I switch the direction around to get the ceiling, then use another * -1 to return to the original sign. The math is done from left to right.

>>> 3/2
1.5
>>> 3//2 # floor
1
>>> -(-3//2) # ceil
2