Changing order of ordered dictionary in python

OrderedDicts are ordered by insertion order. So you would have to construct a new OrderedDict by looping over the key:value pairs in the original object. There is no OrderedDict method that will help you.

So you could create a tuple to represent the idea order of the keys, and then iterate over that to create a new OrderedDict.

key_order = ('animal', 'people', 'food', 'drink')
new_queue = OrderedDict()
for k in key_order:
    new_queue[k] = queue[k]

Or more eloquently

OrderedDict((k, queue[k]) for k in key_order)

Edit: You can write a custom function (warning, this works but is very quick and dirty):

EDIT: Fixed bug that occurs when you try to move forward

import collections

def move_element(odict, thekey, newpos):
    odict[thekey] = odict.pop(thekey)
    i = 0
    for key, value in odict.items():
        if key != thekey and i >= newpos:
            odict[key] = odict.pop(key)
        i += 1
    return odict

queue = collections.OrderedDict()

queue["animals"] = ["cat", "dog", "fish"]
queue["food"] = ["cake", "cheese", "bread"]
queue["people"] = ["john", "henry", "mike"]
queue["drinks"] = ["water", "coke", "juice"]
queue["cars"] = ["astra", "focus", "fiesta"]

print queue

queue = move_element(queue, "people", 1)

print queue

I think you'll have to do it manually:

>>> keys = list(queue)
>>> keys
['animals', 'food', 'people', 'drinks']
>>> keys[1], keys[2] = keys[2], keys[1]
>>> queue = collections.OrderedDict((key, queue[key]) for key in keys)
>>> list(queue)
['animals', 'people', 'food', 'drinks']