char!=(signed char), char!=(unsigned char)

While most integral types like short and int default to being signed, char does not have a default signage in C++.

It is neither the type signed char nor unsigned char, so implementations may decide whether it is signed.

It's a common mistake that C++ programmers run into when they use char as an 8 bit integer type.

Here is your answer from the standard:

3.9.1 Fundamental types [basic.fundamental]

Objects declared as characters (char) shall be large enough to store any member of the implementation's basic character set. If a character from this set is stored in a character object, the integral value of that character object is equal to the value of the single character literal form of that character. It is implementation-defined whether a char object can hold negative values. Characters can be explicitly declared unsigned or signed. Plain char, signed char, and unsigned char are three distinct types. A char, a signed char, and an unsigned char occupy the same amount of storage and have the same alignment requirements (basic.types); that is, they have the same object representation. For character types, all bits of the object representation participate in the value representation. For unsigned character types, all possible bit patterns of the value representation represent numbers. These requirements do not hold for other types. In any particular implementation, a plain char object can take on either the same values as a signed char or an unsigned char; which one is implementation-defined.