Check if all values of array are equal

This works. You create a method on Array by using prototype.

if (Array.prototype.allValuesSame === undefined) {
  Array.prototype.allValuesSame = function() {
    for (let i = 1; i < this.length; i++) {
      if (this[i] !== this[0]) {
        return false;
      }
    }
    return true;
  }
}

Call this in this way:

let a = ['a', 'a', 'a'];
let b = a.allValuesSame(); // true
a = ['a', 'b', 'a'];
b = a.allValuesSame();     // false

const allEqual = arr => arr.every( v => v === arr[0] )
allEqual( [1,1,1,1] )  // true

Or one-liner:

[1,1,1,1].every( (val, i, arr) => val === arr[0] )   // true

Array.prototype.every (from MDN) : The every() method tests whether all elements in the array pass the test implemented by the provided function.

Edit: Be a Red ninja:

!!array.reduce(function(a, b){ return (a === b) ? a : NaN; });

Results:

var array = ["a", "a", "a"] => result: "true"
var array = ["a", "b", "a"] => result: "false"
var array = ["false", ""] => result: "false"
var array = ["false", false] => result: "false"
var array = ["false", "false"] => result: "true"
var array = [NaN, NaN] => result: "false" 

---

Warning:

var array = [] => result: TypeError thrown

This is because we do not pass an initialValue. So, you may wish to check array.length first.