Check if an array contains (only) numeric values
Shortest solution, evals to true
if and only if every item is (coercible to) a number:
!yourArray.some(isNaN)
Using simple JavaScript, you can do something like this:
var IsNumericString = ["21","53","92","79"].filter(function(i){
return isNaN(i);
}).length > 0;
It will return true;
I had a similar need but wanted to verify if a list contained only integers (i.e., no decimals). Based on the above answers here's a way to do that, which I posting in case anyone needs a similar check.
Thanks @Touffy, for your suggestion.
let x = [123, 234, 345];
let y = [123, 'invalid', 345];
let z = [123, 234.5, 345];
!x.some(i => !Number.isInteger(i)) // true
!y.some(i => !Number.isInteger(i)) // false
!z.some(i => !Number.isInteger(i)) // false