Check if geo-point is inside or outside of polygon
Here is a possible solution to my problem.
- Geographical coordinates must be stored properly. Example
np.array([[Lon_A, Lat_A], [Lon_B, Lat_B], [Lon_C, Lat_C]])
- Create the polygon
- Create the point to be tested
- Use
polygon.contains(point)
to test if point is inside (True
) or outside (False
) the polygon.
Here is the missing part of the code:
from shapely.geometry import Point
from shapely.geometry.polygon import Polygon
lons_lats_vect = np.column_stack((lons_vect, lats_vect)) # Reshape coordinates
polygon = Polygon(lons_lats_vect) # create polygon
point = Point(y,x) # create point
print(polygon.contains(point)) # check if polygon contains point
print(point.within(polygon)) # check if a point is in the polygon
Note: the polygon does not take into account great circles, therefore it is necessary to split the edges into many segments thus increasing the number of vertices.
Special case: If point lies on borders of Polygon
E.g. print(Polygon([(0, 0), (1, 0), (1, 1)]).contains(Point(0, 0)))
will fail
So one can use
print(polygon.touches(point)) # check if point lies on border of polygon
Another way to do it is by using the even-odd algorithm explained in this link https://wrf.ecse.rpi.edu//Research/Short_Notes/pnpoly.html The python code is given in wikipedia https://en.wikipedia.org/wiki/Even–odd_rule
Folks, just remember that the ORDER OF POINTS that make the polygon MATTER! I mean, different order results in different polygons.
There is also an emerging python library turfpy. which is used for geospatial analysis.
PyPI
Github
Example:
from turfpy.measurement import boolean_point_in_polygon
from geojson import Point, Polygon, Feature
point = Feature(geometry=Point((-46.6318, -23.5523)))
polygon = Polygon(
[
[
(-46.653, -23.543),
(-46.634, -23.5346),
(-46.613, -23.543),
(-46.614, -23.559),
(-46.631, -23.567),
(-46.653, -23.560),
(-46.653, -23.543),
]
]
)
boolean_point_in_polygon(point, polygon)