Check if one list contains all items from another list in order

This takes each part of ListA and compares it with ListB with SequenceEqual:

bool containsSameSequence = ListA
    .Where((item, index) => index <= ListA.Count - ListB.Count)
    .Select((item, index) => ListA.Skip(index).Take(ListB.Count))
    .Any(part => part.SequenceEqual(ListB));

Demo

It returns true on the first matching sequence.

Here's a quick way:

var equal = listA.Count - listB.Count < 0 
    ? false 
    : Enumerable.Range(0, listA.Count - listB.Count).Any(i => 
      listA.Skip(i).Take(listB.Count).SequenceEqual(listB));

---

However, I'd prefer to use an extension method like this:

public static bool ContainsSequence<T>(this IEnumerable<T> outer, 
                                       IEnumerable<T> inner)
{
    var innerCount = inner.Count();
    for(int i = 0; i < outer.Count() - innerCount; i++)
    {
        if(outer.Skip(i).Take(innerCount).SequenceEqual(inner))
            return true;
    }

    return false;
 }

which you can call like:

var equals = listA.ContainsSequence(listB);

---

And here's a more efficient version of the same extension method specific to List<T>:

public static bool ContainsSequence<T>(this List<T> outer, List<T> inner)
{
    var innerCount = inner.Count;

    for (int i = 0; i < outer.Count - innerCount; i++)
    {
        bool isMatch = true;
        for (int x = 0; x < innerCount; x++)
        {
            if (!outer[i + x].Equals(inner[x]))
            {
                isMatch = false;
                break;
            }
        }

        if (isMatch) return true;
    }

    return false;
}