check if palindrome js code example

Example 1: palindrome in javascript

function palindrome(str) {

    var len = str.length;
    var mid = Math.floor(len/2);

    for ( var i = 0; i < mid; i++ ) {
        if (str[i] !== str[len - 1 - i]) {
            return false;
        }
    }

    return true;
}

Example 2: how to check palindrome in javascript for lowercase and uppercase

function palindrome(str) {
  var re = /[\W_]/g;
  var lowRegStr = str.toLowerCase().replace(re, '');
  var reverseStr = lowRegStr.split('').reverse().join(''); 
  return reverseStr === lowRegStr;
}
palindrome("A man, a plan, a canal. Panama");

Example 3: palindrome javascript

function palindrome(str) {
 var splitted = str.split("");
 var reversed = splitted.reverse("");
 var joined = reversed.join("");
 return joined.toLowerCase().replace(/[^0-9a-z]/gi, '') == str.toLowerCase().replace(/[^0-9a-z]/gi, '')
}

Example 4: javascript palindrome check

function palindrome(str) {
 // Step 1. The first part is the same as earlier
 var re = /[^A-Za-z0-9]/g; // or var re = /[\W_]/g;
 str = str.toLowerCase().replace(re, '');

 // Step 2. Create the FOR loop
 var len = str.length; // var len = "A man, a plan, a canal. Panama".length = 30
 
 for (var i = 0; i < len/2; i++) {
   if (str[i] !== str[len - 1 - i]) { // As long as the characters from each part match, the FOR loop will go on
       return false; // When the characters don't match anymore, false is returned and we exit the FOR loop
   }
   /* Here len/2 = 15
      For each iteration: i = ?    i < len/2    i++    if(str[i] !== str[len - 1 - i])?
      1st iteration:        0        yes         1     if(str[0] !== str[15 - 1 - 0])? => if("a"  !==  "a")? // false
      2nd iteration:        1        yes         2     if(str[1] !== str[15 - 1 - 1])? => if("m"  !==  "m")? // false      
      3rd iteration:        2        yes         3     if(str[2] !== str[15 - 1 - 2])? => if("a"  !==  "a")? // false  
      4th iteration:        3        yes         4     if(str[3] !== str[15 - 1 - 3])? => if("n"  !==  "n")? // false  
      5th iteration:        4        yes         5     if(str[4] !== str[15 - 1 - 4])? => if("a"  !==  "a")? // false
      6th iteration:        5        yes         6     if(str[5] !== str[15 - 1 - 5])? => if("p"  !==  "p")? // false
      7th iteration:        6        yes         7     if(str[6] !== str[15 - 1 - 6])? => if("l"  !==  "l")? // false
      8th iteration:        7        yes         8     if(str[7] !== str[15 - 1 - 7])? => if("a"  !==  "a")? // false
      9th iteration:        8        yes         9     if(str[8] !== str[15 - 1 - 8])? => if("n"  !==  "n")? // false
     10th iteration:        9        yes        10     if(str[9] !== str[15 - 1 - 9])? => if("a"  !==  "a")? // false
     11th iteration:       10        yes        11    if(str[10] !== str[15 - 1 - 10])? => if("c" !==  "c")? // false
     12th iteration:       11        yes        12    if(str[11] !== str[15 - 1 - 11])? => if("a" !==  "a")? // false
     13th iteration:       12        yes        13    if(str[12] !== str[15 - 1 - 12])? => if("n" !==  "n")? // false
     14th iteration:       13        yes        14    if(str[13] !== str[15 - 1 - 13])? => if("a" !==  "a")? // false
     15th iteration:       14        yes        15    if(str[14] !== str[15 - 1 - 14])? => if("l" !==  "l")? // false
     16th iteration:       15        no               
    End of the FOR Loop*/
 }
 return true; // Both parts are strictly equal, it returns true => The string is a palindrome
}

palindrome("A man, a plan, a canal. Panama");