Checking if a number is an Integer in Java

One example more :)

double a = 1.00

if(floor(a) == a) {
   // a is an integer
} else {
   //a is not an integer.
}

In this example, ceil can be used and have the exact same effect.

Quick and dirty...

if (x == (int)x)
{
   ...
}

edit: This is assuming x is already in some other numeric form. If you're dealing with strings, look into Integer.parseInt.

/**
 * Check if the passed argument is an integer value.
 *
 * @param number double
 * @return true if the passed argument is an integer value.
 */
boolean isInteger(double number) {
    return number % 1 == 0;// if the modulus(remainder of the division) of the argument(number) with 1 is 0 then return true otherwise false.
}