Combining a vector of strings

Assuming this is question 6.8, it doesn't say you have to use accumulate - it says use "a library algorithm". However, you can use accumulate:

#include <numeric>
    
int main () {
    std::string str = "Hello World!";
    std::vector<std::string> vec(10,str);
    std::string a = std::accumulate(vec.begin(), vec.end(), std::string(""));
    std::cout << a << std::endl;
}

All that accumulate does is set 'sum' to the third parameter, and then for all of the values 'val' from first parameter to second parameter, do:

sum = sum + val

it then returns 'sum'. Despite the fact that accumulate is declared in <numeric> it will work for anything that implements operator+()

---

Note: This solution, while elegant, is inefficient, as a new string will be allocated and populated for each element of vec.

The following snippet compiles in Visual C++ 2012 and uses a lambda function:

int main () {
    string str = "Hello World!";
    vector<string>  vec (10,str);

    stringstream ss;
    for_each(vec.begin(), vec.end(), [&ss] (const string& s) { cat(ss, s); });

    cout << ss.str() << endl;
}

The accumulate example in the 1st answer is elegant, but as sellibitze pointed out, it reallocates with each concatenation and scales at O(N²). This for_each snippet scales at about O(N). I profiled both solutions with 100K strings; the accumulate example took 23.6 secs, but this for_each snippet took 0.054 sec.

I am not sure about your question.Where lies the problem? Its just a matter of a loop.

#include<vector>
#include<string>
#include<iostream>

int main () 
{
    std::string str = "Hello World!";
    std::vector<string>  vec (10,str);

    for(size_t i=0;i!=vec.size();++i)
        str=str+vec[i];
    std::cout<<str;
}

EDIT :

Use for_each() from <algorithm>

Try this:

#include<vector>
#include<string>
#include<iostream>
#include<algorithm>
using namespace std;
string i;
void func(string &k)
{
  i+=k;
}
int main () {
    string str = "Hello World!";
    vector<string>  vec (10,str);

    for_each(vec.begin(),vec.end(),func);
    cout<<i;
    return 0;
  }

How about std::copy?

std::ostringstream os;
std::copy( vec_strings.begin(), vec_string.end(), ostream_iterator<string>( os ) );
cout << os.str() << endl;