Comparing arrays in chai
You can do it with 2 lines :
expect(listFromPage).to.eventually.include.all.members(predefinedArray)
expect(predefinedArray).to.eventually.include.all.members(listFromPage)
With this, you'll check if both arrays contains the same values. But order does not matter.
Seeing as this was marked as resolved earlier, I tried doing the same thing as in the accepted answer. It probably worked back then, but doesn't seem to work anymore:
expect([1, 2, 3, 4]).to.have.all.members([2, 4, 3, 1]);
Gives the following error:
AssertionError: expected 1 to be an array
I did a little more research and found a pull request that added this functionality back in 2013:
https://github.com/chaijs/chai/pull/153
So the official way of doing this now is like this:
expect([1, 2, 3, 4]).to.have.same.members([2, 4, 3, 1]);
For completeness, here's the error that two different sets produces:
AssertionError: expected [ 1, 2, 3, 4 ] to have the same members as [ 4, 3, 1 ]
Hope this helps anyone searching for the same answer now. :-)
From the future, the way that worked for me, was to use .deepEqual which did the trick for me
assert.deepEqual(['name'], ['name'], 'this must be same to proceed');
It's not entirely clear from the documentation, but .to.have.all.members
seems to work. I could only find a mention of this feature for .keys
, but looks like it also works for .members
with arrays.