Comparing NSNumbers in Objective C

I assume number1 and number2 are pointers to objects. The < sign is comparing the pointers.

You need to compare the actual floatValue or doubleValue

if ([number1 doubleValue] < [number2 doubleValue]) 

....

For cases where you simply want to test whether two NSNumber properties hold the same value, then from the Apple documentation it seems that using

- (BOOL)isEqualToNumber:(NSNumber *)aNumber

is the most straightforward and efficient way to compare two NSNumber values.

For example:

if ([someNumber isEqualToNumber:someOtherNumber])
{
    // The numbers hold the same value
}
else
{
    // The numbers hold different values
}

The documentation also says "This method is more efficient than compare: if you know the two objects are numbers."

Whenever you need to know whether a value is smaller or greater, they offer the

- (NSComparisonResult)compare:(NSNumber *)aNumber

method, but personally I would prefer at that point to just pull out the integer values (or double values) and use regular < and > operators to do the comparison, because that makes the code much easier to read, like so:

if (firstNumber.intValue > secondNumber.intValue)
{
    // First number is greater than the second number
}
else if (firstNumber.intValue == secondNumber.intValue)
{
    // The two numbers have the same value
}
else
{
    // The first number is smaller than the second number
}

Something like that is much easier to read than calls to -compare:, in my opinion.

Erik

NSNumber has a method for comparison: - (NSComparisonResult)compare:(NSNumber*)aNumber

if([numberOne compare:numberTwo] == NSOrderedSame) 
{
      // proceed
}