Compute 100th derivative

Write your function as $$ \frac{x^2 + 1}{x^3 - x} = \frac{1}{x-1} + \frac{1}{x+1} - \frac{1}{x} $$


Hint: since $x^3-x=x(x-1)(x+1)$ you can easily split $f(x)$ into partial fractions.

Tags:

Calculus

Derivatives

Partial Fractions

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