Compute $\int\frac{x}{x+1}dx$

Note that

$$\int \frac{x}{x+1} dx = \int \frac{x +1-1}{x+1}dx=\int \left(1-\frac{1}{x+1}\right)dx=x-\ln|x+1|\color{red}{+C}$$

Tags:

Substitution

Integration

Calculus

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