Convert ByteArray to UUID java
The method nameUUIDFromBytes()
converts a name into a UUID. Internally, it applied hashing and some black magic to turn any name (i.e. a string) into a valid UUID.
You must use the new UUID(long, long);
constructor instead:
public static String getGuidFromByteArray(byte[] bytes) {
ByteBuffer bb = ByteBuffer.wrap(bytes);
long high = bb.getLong();
long low = bb.getLong();
UUID uuid = new UUID(high, low);
return uuid.toString();
}
But since you don't need the UUID object, you can just do a hex dump:
public static String getGuidFromByteArray(byte[] bytes) {
StringBuilder buffer = new StringBuilder();
for(int i=0; i<bytes.length; i++) {
buffer.append(String.format("%02x", bytes[i]));
}
return buffer.toString();
}
Try doing same process in reverse:
public static String getGuidFromByteArray(byte[] bytes)
{
ByteBuffer bb = ByteBuffer.wrap(bytes);
UUID uuid = new UUID(bb.getLong(), bb.getLong());
return uuid.toString();
}
For both building and parsing your byte[], you really need to consider the byte order.
Try:
public static String getGuidFromByteArray(byte[] bytes) {
ByteBuffer bb = ByteBuffer.wrap(bytes);
UUID uuid = new UUID(bb.getLong(), bb.getLong());
return uuid.toString();
}
Your problem is that UUID.nameUUIDFromBytes(...)
only creates type 3 UUIDs, but you want any UUID type.