Convert java.lang.String to Scala string

It's not a wrapper, but actually java.lang.String. No need in additional hassle:

» touch 123
» scala
...

val foo = new java.io.File("123")
// java.io.File = 123

// Get name is a java api, which returns Java string

foo.getName.toInt
// res2: Int = 123

java.lang.String is implicitly amended with Scala specific string methods so no manual conversion should be necessary.