Convert kebab-case to camelCase - Javascript
You can also try regex.
camelize = s => s.replace(/-./g, x=>x.toUpperCase()[1])
Looks only for hyphen followed by any character, and capitalises it and replaces the hyphen+character with the capitalised character.
To keep your existing code, I've just added a check on the index that will return item
instead of the transformed item if item is 0 (falsy), since the problem is just that you are upper-casing the first item as well, while you shouldn't.
In a nutshell, the inline expression becomes: (item, index) => index ? item.charAt(0).toUpperCase() + item.slice(1).toLowerCase() : item
, because:
- If index is not falsy (so, if index is > 0 in your context), the capitalized string is returned.
- Otherwise, the current item is returned.
Of course, this could be cleaner and likely single line, but I wanted to stay as close as possible to your code so that you could understand what was wrong:
function camelize(str){
let arr = str.split('-');
let capital = arr.map((item, index) => index ? item.charAt(0).toUpperCase() + item.slice(1).toLowerCase() : item.toLowerCase());
// ^-- change here.
let capitalString = capital.join("");
console.log(capitalString);
}
camelize("my-kebab-string");
As a side note, you could've found a potential cleaner answer here: Converting any string into camel case
The first method is to just transform to lower case the first entry of your capital
array, like this:
capital[0] = capital[0].toLowerCase();
Another method, which I think to be more efficient, is to pass another parameter to the map
callback, which is the index
. Take a look at this for further reading:
https://www.w3schools.com/jsref/jsref_map.asp
So you transform to upper case only if (index > 0)
.
Like this:
let capital = arr.map((item, index) => index ? item.charAt(0).toUpperCase() + item.slice(1).toLowerCase() : item);