Convert timedelta to floating-point
In Python 3.2 or higher, you can divide two timedelta
s to give a float. This is useful if you need the value to be in units other than seconds.
time_d_min = time_d / datetime.timedelta(minutes=1)
time_d_ms = time_d / datetime.timedelta(milliseconds=1)
You could use numpy to solve that:
import pandas as pd
import numpy as np
time_d = datetime_1 - datetime_2
#for a single value
number_of_days =pd.DataFrame([time_d]).apply(np.float32)
#for a Dataframe
number_of_days = time_d.apply(np.float32)
Hope it is helpful!
You could use the total_seconds
method:
time_d_float = time_d.total_seconds()