Converting Python dict to kwargs?
Use the double-star (aka double-splat?) operator:
func(**{'type':'Event'})
is equivalent to
func(type='Event')
Here is a complete example showing how to use the **
operator to pass values from a dictionary as keyword arguments.
>>> def f(x=2):
... print(x)
...
>>> new_x = {'x': 4}
>>> f() # default value x=2
2
>>> f(x=3) # explicit value x=3
3
>>> f(**new_x) # dictionary value x=4
4
**
operator would be helpful here.
**
operator will unpack the dict elements and thus **{'type':'Event'}
would be treated as type='Event'
func(**{'type':'Event'})
is same as func(type='Event')
i.e the dict elements would be converted to the keyword arguments
.
FYI
*
will unpack the list elements and they would be treated as positional arguments
.
func(*['one', 'two'])
is same as func('one', 'two')